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Hint: In set theory, the subtraction of a set A from a set B is given by the set obtained by removing all the elements of the set A from the set B. Using this concept, we can solve this question.

__Complete step-by-step answer:__

Before proceeding with the question, we must know the concept that will be required to solve this question.

Let us assume that we are given two sets A and B. In the set theory, the subtraction of the A from the set B which is denoted by B – A is given by the set obtained by removing all the elements of set A from the set B.

The shaded part in the above venn diagram represents the set B – A.

In this question, we are given set A = {3, 6, 12, 15, 18, 21} and set B = {4, 8, 12, 16, 20}. We are required to find B – A.

We can clearly observe that in set B, the only element which is also present in set A is 12. So, B – A is given by the set obtained after removing the element 12 from the set B.

$\Rightarrow $ B – A = {4, 8, 16, 20}

Hence, the answer is the set {4, 8, 16, 20}.

Note: There is a possibility that one may remove the elements of set B from the set A instead of removing the elements of set A from the set B to find B – A which will give us an incorrect answer.

Before proceeding with the question, we must know the concept that will be required to solve this question.

Let us assume that we are given two sets A and B. In the set theory, the subtraction of the A from the set B which is denoted by B – A is given by the set obtained by removing all the elements of set A from the set B.

The shaded part in the above venn diagram represents the set B – A.

In this question, we are given set A = {3, 6, 12, 15, 18, 21} and set B = {4, 8, 12, 16, 20}. We are required to find B – A.

We can clearly observe that in set B, the only element which is also present in set A is 12. So, B – A is given by the set obtained after removing the element 12 from the set B.

$\Rightarrow $ B – A = {4, 8, 16, 20}

Hence, the answer is the set {4, 8, 16, 20}.

Note: There is a possibility that one may remove the elements of set B from the set A instead of removing the elements of set A from the set B to find B – A which will give us an incorrect answer.