Patrick B. answered • 06/13/20

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(a)

P(t) = 3189 - 38(t-2012) where t is the year

= 3189 - 38t + 76456

= 79645 - 38t

(b)

3000 = 79645 - 38t

-76645 = -38t

t= 2016.9736842105263157894736842105

hmmmm.... expect 3000 of them in 2017

(c) P(2019) = 2923

note that 3000-38-38 = 2924